T check Task
MOHA 570

Directions: A well being care researcher wish to reply the next analysis Question Assignment: On common, are for-profit nursing houses bigger (primarily based on complete variety of beds) than amenities of one other kind (non-profit and governmental)? Compose a null and different speculation beneath:

H1:
H0:

SPSS t-test outputs are beneath. Write an APA fashion outcomes paragraph explaining the outcomes, conclusions, assumptions and limitations. Talk about if t-test was the suitable check choice by way of skewed vs. usually distributed knowledge.

Case Processing Abstract
for revenue=1, nonprofit and GV=zero Instances
Legitimate Lacking Whole
N P.c N P.c N P.c
Whole Variety of Beds .00 115 100.zero% zero zero.zero% 115 100.zero%
1.00 283 100.zero% zero zero.zero% 283 100.zero%

Descriptives
for revenue=1, nonprofit and GV=zero Statistic Std. Error
Whole Variety of Beds .00 Imply 93.97 5.071
95% Confidence Interval for Imply Decrease Sure 83.93
Higher Sure 104.02
5% Trimmed Imply 90.08
Median 87.00
Variance 2957.657
Std. Deviation 54.384
Minimal 12
Most 300
Vary 288
Interquartile Vary 74
Skewness 1.zero74 .226
Kurtosis 1.858 .447
1.00 Imply 112.01 2.835
95% Confidence Interval for Imply Decrease Sure 106.43
Higher Sure 117.59
5% Trimmed Imply 110.12
Median 114.00
Variance 2275.269
Std. Deviation 47.700
Minimal 13
Most 298
Vary 285
Interquartile Vary 57
Skewness .644 .145
Kurtosis .706 .289

Assessments of Normality
for revenue=1, nonprofit and GV=zero Kolmogorov-Smirnova Shapiro-Wilk
Statistic df Sig. Statistic df Sig.
Whole Variety of Beds .00 .108 115 .002 .928 115 .00zero
1.00 .105 283 .00zero .971 283 .00zero
a. Lilliefors Significance Correction

T-test with outliers eliminated (Instances 81 [TOTBED=392] and 94 [TOTBED= 356] from NP = zero Group)
Group Statistics
for revenue=1, nonprofit and GV=zero N Imply Std. Deviation Std. Error Imply
Whole Variety of Beds .00 115 93.97 54.384 5.071
1.00 283 112.01 47.700 2.835

Impartial Samples Check
Levene’s Check for Equality of Variances t-test for Equality of Means
F Sig. t df Sig. (2-tailed) Imply Distinction Std. Error Distinction 95% Confidence Interval of the Distinction
Decrease Higher
Whole Variety of Beds Equal variances assumed Three.548 .060 -Three.280 396 .001 -18.033 5.498 -28.842 -7.224
Equal variances not assumed -Three.104 188.950 .002 -18.033 5.810 -29.494 -6.572

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