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Enter your LETTER answers HERE |
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Note: |
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When done, using your last name and firstname, save THIS FILE as, |
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e270Lastname Firstname HW6 |
(No space between E270 and Last name) |
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and e-mail it to |
[email protected] |
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Example: |
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e270Smith Adam HW6 |
YES |
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e270 Smith Adam HW6 |
NO |
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PAY ATTENTION! |
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1 |
Which of the following statements about Type I and Type II errors is correct |
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a |
Type I: Reject a true alternative hypothesis. Type II: Do not reject a false alternative. |
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b |
Type I: Do not reject a false null hypothesis. Type II: Reject a true null hypothesis. |
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c |
Type I: Reject a false null hypothesis. Type II: Reject a true null hypothesis. |
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d |
Type I: Reject a true null hypothesis. Type II: Do not reject a false null hypothesis. |
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2 |
You are reading a report that contains a hypothesis test you are interested in. The writer of the report writes that the p-value for the test you are interested in is 0.061, but does not tell you the value of the test statistic. From this information you can: |
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a |
Not reject the hypothesis at a Probability of Type I error = 0.05, and not reject at a Probability of Type I error = 0.10 |
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b |
Reject the hypothesis at a Probability of Type I error = .05, and reject at a Probability of Type I error = 0.10 |
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c |
Not reject the hypothesis at a Probability of Type I error = .05, but reject the hypothesis at a Probability of Type I error = 0.10 |
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d |
Reject the hypothesis at a Probability of Type I error = .05, but not reject at a Probability of Type I error = 0.10 |
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3 |
The random sample below is obtained to test the following hypothesis about the population mean. |
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H₀: μ ≤ |
120 |
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H₁: μ > |
120 |
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152 |
203 |
67 |
177 |
220 |
101 |
23 |
214 |
134 |
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49 |
53 |
177 |
23 |
128 |
181 |
10 |
103 |
214 |
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198 |
99 |
126 |
183 |
70 |
16 |
148 |
118 |
69 |
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182 |
166 |
199 |
59 |
172 |
40 |
177 |
28 |
42 |
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126 |
104 |
157 |
123 |
199 |
76 |
106 |
162 |
135 |
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174 |
55 |
64 |
126 |
176 |
62 |
13 |
59 |
154 |
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14 |
196 |
164 |
186 |
71 |
150 |
186 |
90 |
140 |
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177 |
189 |
209 |
50 |
26 |
233 |
16 |
28 |
135 |
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169 |
171 |
198 |
116 |
115 |
236 |
176 |
80 |
130 |
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59 |
227 |
212 |
167 |
35 |
61 |
136 |
72 |
123 |
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220 |
100 |
135 |
171 |
70 |
58 |
92 |
28 |
141 |
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52 |
27 |
181 |
138 |
231 |
80 |
115 |
153 |
187 |
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235 |
212 |
235 |
167 |
136 |
16 |
73 |
166 |
156 |
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209 |
128 |
166 |
66 |
234 |
76 |
207 |
154 |
188 |
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210 |
202 |
198 |
14 |
192 |
10 |
11 |
136 |
170 |
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214 |
231 |
28 |
94 |
125 |
214 |
31 |
64 |
72 |
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The level of significance of the test is α = 0.05. Compute the relevant test statistic. |
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This is a(n) _______ (two-tail, upper-tail, lower-tail) test. The test statistic is TS = _______. |
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a |
Upper tail test. |
TS = |
1.34 |
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Do not reject H₀: μ ≤ 120. Conclude that the population mean is not greater than 120. |
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b |
Upper tail test. |
TS = |
1.88 |
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Reject H₀: μ ≤ 120. Conclude that the population mean is greater than 120. |
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c |
Upper tail test. |
TS = |
1.88 |
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Reject H₀: μ ≤ 120. Conclude that the population mean is greater than 120. |
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d |
Lower tail test. |
TS = |
1.88 |
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Do not reject H₀: μ ≤ 120. Conclude that the population mean is less than 120. |
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4 |
Consider the following hypothesis test. |
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H₀: μ ≥ |
15 |
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H₁: μ < |
15 |
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A random sample of n = 15 yielded the following observations |
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8 |
7 |
11 |
11 |
8 |
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13 |
8 |
12 |
13 |
5 |
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21 |
21 |
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15 |
18 |
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Use α = |
0.05 |
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TS = ______ |
CV = ______ |
State the decision rule. |
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a |
-1.743 |
-1.761 |
Do not reject H₀. Conclude the mean is not less than 15. |
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b |
-1.74 |
-1.64 |
Reject H₀. Conclude the mean is less than 15. |
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c |
1.847 |
2.145 |
Do not reject H₀. Conclude the mean is not less than 15. |
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d |
1.847 |
1.761 |
Reject H₀. Conclude the mean is less than 15. |
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5 |
In a recent study, a major fast food restaurant had a mean service time of 164 seconds. The company embarks on a quality improvement effort to reduce the service time and has developed improvements to the service process. The new process will be tested in a sample of stores. The new process will be adopted in all of its stores, if it resulted in decreased service time. To perform the hypothesis test in the previous question, the sample of 54 stores yields the following data (seconds). |
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157 |
115 |
115 |
115 |
134 |
174 |
128 |
136 |
161 |
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127 |
139 |
125 |
145 |
199 |
161 |
182 |
144 |
199 |
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156 |
117 |
129 |
193 |
173 |
146 |
128 |
166 |
185 |
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147 |
136 |
180 |
184 |
116 |
172 |
116 |
193 |
183 |
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184 |
160 |
120 |
161 |
161 |
122 |
191 |
170 |
124 |
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130 |
191 |
170 |
190 |
194 |
139 |
114 |
195 |
183 |
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Use α = |
0.05 |
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|TS| = ______ |
|CV| = ______ |
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a |
2.335 |
1.674 |
Do not reject H₀. The mean is not less than 164 seconds. Do not adopt the new process. |
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b |
2.335 |
1.674 |
Reject H₀. The mean is less than 164 seconds. Adopt the new process. |
c |
1.674 |
1.349 |
Reject H₀. The mean is less than 164 seconds. Adopt the new process. |
d |
1.349 |
1.674 |
Do not reject H₀. The mean is not less than 164 seconds. Do not adopt the new process. |
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6 |
According to Kelley Blue Book, the mean price for one-to three-year-old used cars nationwide is $23,400. to compare the average price of similar used cars in central indiana, a random sample of 120 such cars were selected. The sample mean was $21,824 with a standard deviation of 7,309. Does the sample provide significant evidence that the mean price of one-to-three-year old used cars is different from the national mean price? |
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Use α = |
0.05 |
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a |
p-value = |
0.044 |
Reject H₀. Conclude that the dealership’s price is different from the national mean price. |
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b |
p-value = |
0.124 |
Do not reject H₀. Conclude that the dealership’s price is not different from the national mean price. |
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c |
p-value = |
0.0091 |
Do not reject H₀. Conclude that the dealership’s price is not different from the national mean price. |
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d |
p-value = |
0.0182 |
Reject H₀. Conclude that the dealership’s price is different from the national mean price. |
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7 |
The 2009 mean annual salary of business degree graduates in accounting was $47,900. In a follow-up study in June 2011, a sample of n = 120 graduating accounting majors yielded a sample mean of $49,500 and standard deviation of $8,200. Does the 2011 study provide a significant proof that the mean salary in 2011 is higher than in 2009? Perform this test of hypothesis at a 5% level of significance. |
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a |
p-value = |
0.0524 |
Do not reject H₀. Conclude that the mean annual salary in 2011 is no greater than in 2009. |
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b |
p-value = |
0.0524 |
Reject H₀. Conclude that the mean annual salary in 2011 is greater than in 2009. |
c |
p-value = |
0.0162 |
Reject H₀. Conclude that the mean annual salary in 2011 is greater than in 2009. |
d |
p-value = |
0.0162 |
Do not reject H₀. Conclude that the mean annual salary in 2011 is no greater than in 2009. |
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8 |
A production line operates with a mean filling weight of 16 ounces per container. Overfilling or under filling is a serious problem, and the production line should be shut down if either occurs. A quality control inspector samples 20 items every 2 hours and at that time makes the decision of whether to shut the line down for adjustment. On sample provides the following data: |
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15.8 |
16.1 |
16.2 |
16.1 |
16.1 |
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16.6 |
16.3 |
16.3 |
15.9 |
16.1 |
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16.2 |
15.8 |
16 |
16.3 |
15.9 |
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16 |
15.9 |
16.1 |
15.9 |
16.2 |
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α = |
0.05 |
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Decision Rule: Reject H₀ if TS > CV |
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TS = ______ |
CV = ______ |
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a |
2.000 |
2.093 |
Do not reject H₀. Do not shut the line down for adjustment. |
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b |
2.000 |
1.96 |
Reject H₀. Shut the line down for adjustment. |
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c |
1.786 |
1.729 |
Reject H₀. Shut the line down for adjustment. |
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d |
2.04 |
1.64 |
Do not reject H₀. Shut the line down for adjustment. |
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9 |
The mean cholesterol level in women ages 21-40 in the United States is 190 mg/dl. A study is conducted to determine the cholesterol levels among recent female Asian immigrants. The following is the cholesterol level of a random sample of 108 recent female Asian immigrants. |
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239 |
105 |
251 |
216 |
220 |
120 |
218 |
195 |
129 |
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125 |
196 |
193 |
108 |
178 |
187 |
111 |
176 |
178 |
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141 |
190 |
214 |
180 |
172 |
204 |
118 |
108 |
124 |
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238 |
248 |
253 |
208 |
135 |
146 |
122 |
209 |
254 |
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209 |
232 |
238 |
251 |
110 |
224 |
249 |
219 |
219 |
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124 |
226 |
252 |
189 |
212 |
163 |
205 |
202 |
190 |
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195 |
116 |
125 |
250 |
244 |
140 |
237 |
192 |
191 |
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224 |
105 |
201 |
194 |
136 |
245 |
118 |
150 |
165 |
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132 |
171 |
245 |
166 |
218 |
159 |
130 |
255 |
131 |
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185 |
210 |
223 |
153 |
167 |
174 |
239 |
200 |
107 |
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235 |
123 |
224 |
221 |
106 |
212 |
212 |
130 |
154 |
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200 |
140 |
170 |
202 |
247 |
112 |
153 |
150 |
205 |
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Does the sample provide significant evidence that mean cholesterol level of recent female Asian immigrants is lower than the mean cholesterol level among all females in the United States? State the null and alternative hypotheses. Compute the test statistic and the p-value. State the decision rule. |
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Round x̅ to two decimal points and the standard error to three decimal points. |
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p-value = ______ |
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a |
0.069 |
The evidence is significant at α = 0.05, but not significant at α = 0.01. |
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b |
0.069 |
The evidence is significant at α = 0.10, but not significant at α = 0.05. |
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c |
0.034 |
The evidence is significant at α = 0.05, but not significant at α = 0.01. |
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d |
0.034 |
The evidence is significant at α = 0.01, but not significant at α = 0.05. |
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10 |
We want to test the hypothesis that mothers with low socio-economic status (SES) deliver babies whose birth weights are lower than “normal”. To test this hypothesis, a list is obtained of birth weights from 100 consecutive, full-term, live-born deliveries from the maternity ward of a hospital in a low-SES area. The mean birth weight is x̅ = 115 oz. with a standard deviation s = 24 oz. Nationwide, the mean birth weight in the United States is 120 oz. At α = 0.05, does this sample provide significant evidence that the mean birth weight of babies born to mother with low SES is lower than “normal”? |
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a |
p-value = |
0.0188 |
Reject H₀ at the 5 percent level of significance. Conclude that the mean birth weight of babies born to low-SES mothers is lower than “normal”. |
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b |
p-value = |
0.0188 |
Reject H₀ at the 1 percent level of significance. Conclude that the mean birth weight of babies born to low-SES mothers is lower than “normal”. |
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c |
p-value = |
0.0785 |
Do not reject H₀ at the 5 percent level of significance. Conclude that the mean birth weight of babies born to low-SES mothers is no lower than “normal”. |
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d |
p-value = |
0.0785 |
Do not reject H₀ at the 10 percent level of significance. Conclude that the mean birth weight of babies born to low-SES mothers is no lower than “normal”. |
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11 |
At Western University the historical mean scholarship examination score of entering students has been 900. Each year a sample of applications is taken to see whether the examination scores are at the same level as in previous years. The null hypothesis tested is H₀: μ = 900. A sample of n = 81 students in this year’s class provided a sample mean score of x̅ = 935 and a standard deviation of s = 180. |
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First build a 95% confidence interval for the population mean score. |
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a |
The confidence interval captures µ₀ = 900. Do not reject H₀. Conclude that the current mean score is not different from the historical mean score. |
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b |
Compared to the MOE, x̅ − µ₀ is within the margin of error. Conclude that the current mean score is not different from the historical mean score. |
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c |
Compared to the MOE, x̅ − µ₀ is outside the margin of error. Conclude that the current mean score is different from the historical mean score. |
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d |
Both a and b are correct. |
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12 |
Consider the following hypothesis test. |
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H₀: π ≤ |
0.5 |
H₁: π > |
0.5 |
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A sample of n = 200 provided a sample proportion of p̅ = 0.57. At α = 0.05, what is your conclusion? |
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TS = ______ |
CV = ______ |
State the decision rule. |
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a |
1.98 |
1.64 |
Conclude the population proportion is no greater than 0.50. |
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b |
1.98 |
1.64 |
Conclude the population proportion is greater than 0.50. |
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c |
2.98 |
1.96 |
Conclude the population proportion is no greater than 0.50. |
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d |
2.98 |
1.96 |
Conclude the population proportion is greater than 0.50. |
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13 |
In the previous question, the prob value for the test is: |
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a |
0.0239 |
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b |
0.0427 |
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c |
0.0618 |
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d |
0.0808 |
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Next THREE questions are based on the following |
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Consider the following hypothesis test. |
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H₀: π ≥ 0.75 |
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H₁: π < 0.75 |
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Compute the test statistic and the p-value for the following three cases. |
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14 |
n = |
200 |
p̅ = |
0.70 |
α = |
0.05 |
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a |
p-value = |
0.0258 |
Conclude that the population proportion is not less than 0.75. |
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b |
p-value = |
0.0258 |
Conclude that the population proportion is less than 0.75. |
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c |
p-value = |
0.0516 |
Conclude that the population proportion is not less than 0.75. |
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d |
p-value = |
0.0516 |
Conclude that the population proportion is less than 0.75. |
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15 |
n = |
200 |
p̅ = |
0.70 |
α = |
0.10 |
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a |
p-value = |
0.0516 |
Conclude that the population proportion is less than 0.75. |
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b |
p-value = |
0.0516 |
Conclude that the population proportion is not less than 0.75. |
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c |
p-value = |
0.0258 |
Conclude that the population proportion is less than 0.75. |
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d |
p-value = |
0.0258 |
Conclude that the population proportion is not less than 0.75. |
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16 |
n = |
900 |
p̅ = |
0.72 |
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a |
p-value = |
0.0188 |
Reject H₀ at α = 0.10, but do not reject at α = 0.05. |
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b |
p-value = |
0.0188 |
Reject H₀ at α = 0.05, but do not reject at α = 0.01. |
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c |
p-value = |
0.0672 |
Reject H₀ at α = 0.10, but do not reject at α = 0.05. |
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d |
p-value = |
0.0672 |
Reject H₀ at α = 0.05, but do not reject at α = 0.10. |
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17 |
The Center for Workforce Development found that 40% of Internet users received more than 15 e-mail messages per day in 2008. In 2012, a similar study on the use of e-mail was repeated. The purpose of the study was see whether use of e-mail has increased. Formulate the null and alternative hypotheses to determine whether an increase has occurred in the proportion of Internet users receiving more than 10 e-mail messages per day. |
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To test the hypothesis at a 5% level of significance, a sample of 420 Internet users found 189 receiving more than 10 e-mail messages per day. Compute the test statistic and the p-value. |
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p-value = ______. |
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a |
0.0183 |
Reject H₀ at α = 0.10. Conclude the population proportion is greater than 0.40. |
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b |
0.0183 |
Reject H₀ at α = 0.05. Conclude the population proportion is greater than 0.40. |
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c |
0.0544 |
Do not reject H₀ at α = 0.05. Conclude the population proportion is not greater than 0.40. |
d |
Both a and b are correct. |
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18 |
We want to test the hypothesis that at least 75% of drivers on a freeway violate the speed limit. In a random sample of n = 900 vehicles, 657 violated the speed limit. Compute the sample proportion. |
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State the null and alternative hypotheses and the decision rule. |
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a |
Reject H₀ at α = 10% and conclude less than 75% of drivers violate the speed limit. But, do not reject H₀ at α = 5% and conclude 75% or more of drivers violate the speed limit. |
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b |
Reject H₀ at α = 5%. Conclude less than 75% of drivers violate the speed limit. |
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c |
Reject H₀ at α = 5%. Conclude more than 75% of drivers violate the speed limit. |
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d |
Reject H₀ at α = 1%. Conclude less than 75% of drivers violate the speed limit. |
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19 |
At least 20% of all workers are believed to be willing to work fewer hours for less pay to obtain more time for personal and leisure activities. A recent poll consisting of 600 respondents found 17% willing to work fewer hours for less pay to obtain more personal and leisure time. At 5% level of significance, does the sample result support the claim that at least 20% of all workers are willing to work fewer hours for less pay to obtain more time for personal and leisure activities? Round the proportion to two decimal point. |
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a |
1.64 |
1.84 |
Do not reject H₀. Conclude that no less than 20% are willing to work fewer hours for less pay to obtain more time for personal and leisure activities. |
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b |
1.84 |
1.96 |
Do not reject H₀. Conclude that no less than 20% are willing to work fewer hours for less pay to obtain more time for personal and leisure activities. |
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c |
1.84 |
1.64 |
Reject H₀. Conclude that less than 20% are willing to work fewer hours for less pay to obtain more time for personal and leisure activities. |
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d |
1.56 |
1.64 |
Do not reject H₀. Conclude that no less than 20% are willing to work fewer hours for less pay to obtain more time for personal and leisure activities. |
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20 |
In the previous question, the p-value is _______. |
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a |
0.0594 |
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b |
0.0329 |
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c |
0.0233 |
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d |
0.0158 |
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